Math, asked by amankurella1606, 7 hours ago

A man of money is to be distributed among A,B,C,D in the proportion of 5:2:4:3. If C gets Rs. 1000/- more than D what is B' s share?​

Answers

Answered by jagruti6551
2

Answer:

Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively

Then, 4x - 3x = 1000

⇒ x = 1000

∴ B's share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000

Answered by subha2007293
0

Answer:

let x be the ratio factor .

so , 5x+2x+4x+3x = total money .

so, we can say 5*x is the money given to A,

2*x is the money given to B,

4*x is the money given to C,

3*x is the money given to D.

now , it is said that C gets 1000 more than D .

ie difference between the amount C and D get is 1000.

so ,

4*x-3*x=1000.

x=1000.

so we found the ratio factor to be 1000.

now the amount of money B get is equal to 2*x = 2*1000= 2000.

therefore the share of B is 2000.

hope this explanation was helpful.

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