Question

a man of weight W is standing on a lift which is moving upwards with an acceleration a. what is the apparent weight of the man

Answer 1

Upward Acceleration=a
Downward Acceleration=g
Since lift is moving up so upward acceleration is greater than downward acceleration hence, we have net acceleration=(a-g) acting upward, So
weight, W=mass of the man× (a-g) acceleration

Answer 2

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HERE IS UR ANSWER....................

Upward Acceleration=a

Downward Acceleration=g

Since lift is moving up so upward acceleration is greater than downward acceleration hence, we have net acceleration=(a-g) acting upward

so, weight=mass of the man× (a-g) acceleration

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