Question

a man offers 2 flowers on even days,3 flowers on odd days divisible by 3 and offer 2 extra flowers on the days divisible by 5,how many flowers did he offer in april 1984

Answer 1

Answer:

67

Step-by-step explanation:

No. of days in April 1984 = 30

No. of days he will offer 2 flowers = 15 days( 15 days r even )

Flowers given = 30 (15*2)

No. of days he will offer 3 flowers = 5 days( 5 days r odd n divisible by 3 )

Flowers given = 25 (5*5)

No. of times he'll give 2 extra = 6 ( 6days divisible by 5 )

Flowers given = 12 (6*2)

So,

Total flowers offered=

30 + 25 + 12

= 67 flowers offered in the month of April 1984