A man on the deck of a ship, 12m above water level, observes that the angle of
elevation of the top of a cliff is 60° and angle of depression of gthe base of the
cliff is 30°. Find the distance of the cliff from the ship and the height of the
cliff.( use V3 = 1.732)
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A man on the deck of a ship, 12m above water level, observes that the angle of
elevation of the top of a cliff is 60° and angle of depression of gthe base of the
cliff is 30°. Find the distance of the cliff from the ship and the height of the
cliff.( use V3 = 1.732)
Step-by-step explanation:
Let the distance of the cliff from the ship be x.
Let the height of the cliff be y.
Hence
tan45
0
=1=
y
h−12
Hence
h−12=y Or
h=y+12 ...(i)
And
tan30
0
=
y
12
=
3
1
Hence
y=12
3
=20.784m
Now
h=y+12
=20.784+12
=32.784m
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