Math, asked by sameerku6312, 2 months ago

A man on the deck of a ship, 12m above water level, observes that the angle of
elevation of the top of a cliff is 60° and angle of depression of gthe base of the
cliff is 30°. Find the distance of the cliff from the ship and the height of the
cliff.( use V3 = 1.732)​

Answers

Answered by chiranthana007
0

Answer:

A man on the deck of a ship, 12m above water level, observes that the angle of

elevation of the top of a cliff is 60° and angle of depression of gthe base of the

cliff is 30°. Find the distance of the cliff from the ship and the height of the

cliff.( use V3 = 1.732)

Step-by-step explanation:

Let the distance of the cliff from the ship be x.

Let the height of the cliff be y.

Hence

tan45

0

=1=

y

h−12

Hence

h−12=y Or

h=y+12 ...(i)

And

tan30

0

=

y

12

=

3

1

Hence

y=12

3

=20.784m

Now

h=y+12

=20.784+12

=32.784m

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