Question

A man on the deck of a ship is 12m above the water level. He observes that the angle of elevation of the top of a cliff is 45degree, and angle of depression of the base is 30 degree . Calculate the distance of the cliff from the ship and height of cliff

Answer 1

Answer:

Let the distance of the cliff from the ship be x.

Let the height of the cliff be y.

Hence

tan45

0

=1=

y

h−12

Hence

h−12=y Or

h=y+12 ...(i)

And

tan30

0

=

y

12

=

3

1

Hence

y=12

3

=20.784m

Now

h=y+12

=20.784+12

=32.784m