A man on the top of a vertical observation tower observes a car moving at a uniform speed coming directly towards it. If it takes 12 minutes for the angle of depression to change from 30⁰ to 45⁰ , how long will the car take to reach the observation tower from this point?
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amrutha1727:
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Let speed of car be v. Then distance between change of angle will be 12v.
→ tan45° = h/vt
→ 1 = h/vt or h = vt
→ tan30° = h/(12v + vt)
By substituting values we get,
→ 1/√3 = vt/(12v + vt)
→ 12v + vt = √3vt
→ 12v = √3vt - vt
→ 12v = vt(√3 - 1)
→ 12v/(√3 - 1) = vt
On rationalizing we get,
→ 12v(√3 + 1)/2 = vt
→ 6(√3 + 1) = t
→ 6 × 1.73 + 6 = t
→ 16.38 minutes = t
Hence car will reach tower within 16.38 minutes.
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