a man on the top of a vertical pole observes a car is moving at a uniform speed coming directly towards it if it takes 19 minutes of the angle of depression to change from 30 to 40, how soon after the car reach the tower?
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Step-by-step explanation:
Let speed of can be vm/min
⇒BC=v×12
In ΔAOC,tan30=
OC
AO
⇒
3
1
=
OC
AO
In ΔAOB,tan45=
OB
AO
⇒1=
OB
AO
⇒OC=
3
AO=
3
OB
⇒OB+BC=
3
OB
⇒OB(
3
−1)⇒BC⇒
BC
OB
=
3
−1
1
Now, t=
v
OB
=
v(
3
−1)
BC
=
3
−1
12
×
3
+1
3
+1
t=6(
3
+1)min
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