a man on the top of he building observes a car at an angle of depression a , where tan a = 1/✓5 and sees that it is moving towards the base of the building. 10 minutes later , the angle of depression of the car is found at b = ✓5 . if the car moves with uniform speed, determine how much more time will it take to reach the base of the tower
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Step-by-step explanation:
Let the tower be represented by CD, the initial position of the car by A and the second position of the car by B.
Let the distance travelled from A to B be d
1
in time t
1
and distance between B to C be d
2
in time t
2
.
In △DCB,tan45=
BC
CD
.
∴BC=CD=d
2
In △ACD,tan30=
AC
CD
∴
3
1
=
d
1
+d
2
d
2
∴d
1
+d
2
=
3
d
2
Since the speed of the car is uniform throughout its journey, we can say
t
1
+t
2
=
3
t
2
∴12+t
2
=
3
t
2
∴t
2
=16.39 min.
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