Question

A man on tour travels first 160 km at 40 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:

Answer 1

60 is the speed
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Answer 2

Answer:

$time \: taken \: to \: cover \: first \: 160 \: km = \frac{160}{64}hr = \frac{5}{2}hr \\ time \: taken \: to \: cover \: next \: 160 \: km = \frac{160}{80}hr = 2hr \\ total \: time \: to \: cover \: (160 \: km + 160 \: km = 320 \: km) = \frac{5}{2}hr + 2hr = \frac{9}{2}hr \\ average \: speed \: for \: the \: 320 \: km = \frac{distance}{time} = \frac{320}{9/2} km/hr = 71 \frac{1}{9}km/hr$