Math, asked by richu9986, 1 month ago

a man out to book for Rs 1040 he sold one at loss of 15% and other at a profit of 36% then he found that it book was sold for the same price and the cost of each book​

Answers

Answered by Korino
2

Answer:

Total selling price = 1040

From given question,

Selling price are same for two books

Therefore selling price of one book = 1040/2 => 520

First Book:

Sold at loss of 15 %

=>15%=[(cp-sp)/cost price]100

Second Book :

Sold at profit of 36%

=> 36%=[(sp-cp)/cost price]100

Since sp = 520

15% = [(cp-520)/cp]*100

36% = [(520-cp)/cp]*100

First Book:

(15/100)cp = (cp -520)*100

15 cp/100 = 100cp - 52000

15 cp = 10000 cp - 5200000

10000cp-15cp = 5200000

9985cp=5200000

cp = 5200000/9985 = 520.781

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