Question

)A man performs 3/5 of the total journey by rail, 17/20 by bus and the remaining 6.5 km on foot. His total journey is:

Answer 1

Answer:

Let the total distance be x ,

now ATQ , 3x/5 +7x/20 +6.5 = x

=> 12x/20 +7x/20 +6.5 = x

=> 19x/20 +6.5 = x

=> x-19x/20 = 6.5

=> x/20 = 6.5

=> x = 6.5×20 = 130km

edit : questions is mis printed as there should be 7/20 and not 17/20. , then the answer i would come 130km

Answer 2

Step-by-step explanation:

I think there is some error in the question

I think it is not 17/20 but 7/20 coz when we add the 3/5 &17/20 It exceeds 1 which is not acceptable

still

3/5x+17/20x+6.5=x

(3×4)+17/20x+6.5=x

29/20x+6.5=x

x-29/20x=6.5

20-29/20x=6.5

-9/20x=6.5

x=6.5×-20/9

x= -14.44km

distance can never be negative

that is why I told question has error

still

3/5x+7/20x+6.5=x

(3×4)+7/20x+6.5=x

19/20x+6.5=x

x-19/20x=6.5

20-19/20x=6.5

1/20x=6.5

x=6.5×20

x=130km

if my answer is correct pls Mark brainliest

thank my answer (your choice)

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