)A man performs 3/5 of the total journey by rail, 17/20 by bus and the remaining 6.5 km on foot. His total journey is:
Answers
Answer:
Let the total distance be x ,
now ATQ , 3x/5 +7x/20 +6.5 = x
=> 12x/20 +7x/20 +6.5 = x
=> 19x/20 +6.5 = x
=> x-19x/20 = 6.5
=> x/20 = 6.5
=> x = 6.5×20 = 130km
edit : questions is mis printed as there should be 7/20 and not 17/20. , then the answer i would come 130km
Step-by-step explanation:
I think there is some error in the question
I think it is not 17/20 but 7/20 coz when we add the 3/5 &17/20 It exceeds 1 which is not acceptable
still
3/5x+17/20x+6.5=x
(3×4)+17/20x+6.5=x
29/20x+6.5=x
x-29/20x=6.5
20-29/20x=6.5
-9/20x=6.5
x=6.5×-20/9
x= -14.44km
distance can never be negative
that is why I told question has error
still
3/5x+7/20x+6.5=x
(3×4)+7/20x+6.5=x
19/20x+6.5=x
x-19/20x=6.5
20-19/20x=6.5
1/20x=6.5
x=6.5×20
x=130km
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