A man places a vertical chain (of mass 'm' and length 'C') on a table slowly. Initially the lower end of the
chain just touches the table. The man drops the chain when half of the chain is in vertical position. Then work done by the man in this process is:
(1)-mgl/2
(2)-mgl/4
(3)-3mgl/8
(4)-mgl/8
pls briefly explain..
( irrelevants will be reported)
Answers
Answered by
2
Answer:
Correct option is
C
−83mgl
In figure.(left side) Potential energy, E1=mg2l
In figure.(right side) Potential energy, E2=2mg4l=8mgl
By using energy conservation, we can write:
change in potential energy = work done by force
⇒E2−E1=work done
⇒8mgl−2mgl=work done
⇒ work done by the man=−83mgl
Hence, the correct option is (C)
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