Question

a man pulling a bag with force of 15 N at angle 60 with horizontal plane. if bag covers a distance of 10 m then work done by man is​

Answer 1

Explanation:

The angle is measured in degrees and you have provided it as 600. Which obviously means 60 since the superscript to signify degree was written as 'O' in your question.

Force, F = 10 N

Angle with horizontal, = Displacement in horizontal direction, S = 2 m 60°

Component of force along horizontal direction is = F cose (10)(cos60) =5 N

So, work done is, W = (5)(2) = 10 J

Second case: Force, F = ?

Angle with horizontal, 0 = 30° Displacement in horizontal direction, S = 2 m

Component of force along horizontal direction is-Fcos0=(F)(cos30)=F(-√3/2)

N

Any nonzero value of force will cause a displacement of 2 m.