Question

A man pulls a suitcase of mass 10.4kg with a
force of 25 N inclined to the horizontal
at an angle of 30. As result the suitcase
accelerates horizontally what is the magnitude
of acceleration ?​

Answer 1

Force in x- direction is

Fcosø=Fx

Fcos30=mAx

10×3^1/2/=10.4 Ax

Ax(acceleration jn horizontal direction)=1.66m/sec^2

Answer 2

Answer:

The magnitude of the acceleration is 2.08m/s².

Explanation:

The force will only act in the horizontal direction. Which is given as,

$F_x=Fcos\theta$         (1)

Where,

$F_x$=force acting in the horizontal direction=ma

F=force inclined to the horizontal

θ=angle on the inclined plane with the horizontal

From the question we have,

Mass of the suitcase(m)=10.4kg

Force inclined to the horizontal(F)=25N

θ=30°

By substituting the values in equation (1) we get;

$F_x=25\times cos30\textdegree$

$10.4\times a=21.65$

$a=\frac{21.65}{10.4}$

$a=2.08m/s^2$

Hence, the magnitude of the acceleration is 2.08m/s².