Question

A man purchased a car and a bike for ₹260000 . he sells the bike at 20°/• loss and the car at 30 percent profit . On the whole transaction he earns a profit of ₹18000 . find the SP OF BIKE​

Answer 1

Answer:

182000

Step-by-step explanation:

Answer : Let the Cost price of Bike = x &

Cost Price of Car = 260000 - x

The man earns profit of 30 % over selling of car =>

Selling Price of Car = 1.30 (260000 - x)

Further, The man loses 20 % over selling of bike =>

Selling Price of Bike = 0.80 * x

On both the transactions, the man earns a profit of Rs 18000

=> Profit for selling of Car = 0.30 (260000 - x)

=> Loss for selling of Bike = 0.20 * x

Since, Net Profit = 18000

Or, 0.30 (260000 - x) - 0.20 x = 18000

or, 78000 - 0.3x - 0.2x = 18000

or, - 0.5 x = 18000 - 78000 = - 60000

or, x = 60000 / 0.5 = 120000

Cost of Bike = 120000 & Cost of Car = 140000

Selling Price of Bike at 20% loss = 96000 &

Selling Price of Car at 30% profit = 140000 * 1.30 = 182000