Math, asked by applechichi2107, 1 year ago

A man purchased a certain number of orange at the rate of 2 for ruppes 5 and sold them at the rate of 3 for rupees 8. in the process, he gained ruppes 20 .find the number of oranges he bought .

Answers

Answered by chinmay2mittal
2
Let the man purchase 6k oranges.==> CP of 6k oranges = Cost of one orange x No. of oranges bought                                 = (5/2)x6k = Rs.15k
SP of 6k oranges = SP of one orange x no. of oranges sold                          = (8/3) x 6k = 16k.
Therefore Profit = SP - CP = 16k -15k = 1k = Rs.20 (given)                                                        ==> k = 20.Hence man purchased oranges = 6k = 6x20 = 120

Answered by aagnavaagna
0
Let the man purchase 6k oranges.
==> CP of 6k oranges = Cost of one orange x No. of oranges bought
                                 = (5/2)x6k = Rs.15k

SP of 6k oranges = SP of one orange x no. of oranges sold
                          = (8/3) x 6k = 16k.

Therefore Profit = SP - CP = 16k -15k = 1k = Rs.20 (given)
                                                        ==> k = 20.
Hence man purchased oranges = 6k = 6x20 = 120

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