Question

A man purchased a plot for Rs. 40,000/- and spent Rs. 6000 on registration etc. He constructed 16 shops on it each costing Rs. 4000/-. He sold 2 shops for Rs. 30,000/- each and the rest at Rs. 10,000 each. Find his gain or loss.​

Answer 1

Solution!!

The concept of profit and loss has to be used here.

CP of plot = Rs 40,000

Spent on registration = Rs 6,000

CP of 1 shop = Rs 4,000

CP of 16 shops = Rs 64,000

Total CP = Rs 40,000 + Rs 6,000 + Rs 64,000

Total CP = Rs 1,10,000

There are 12 shops. 2 are sold for Rs 30,000 each and the remaining are sold at Rs 10,000 each.

SP of 1 shop = Rs 30,000

SP of 2 shops = Rs 60,000

Shops remaining = 12 - 2 = 10

SP of 1 shop = Rs 10,000

SP of 10 shops = Rs 1,00,000

Total SP = Rs 60,000 + Rs 1,00,000

Total SP = Rs 1,60,000

As we see, the total SP is more than total CP.

SP>CP

Profit = SP - CP

Profit = Rs 1,60,000 - Rs 1,10,000

Profit = Rs 50,000

Profit% = (Profit/CP) × 100

Profit% = (50,000/1,10,000) × 100

Profit% = (5/11) × 100

Profit% ≈ 45.45

More information:-

If SP>CP, then it is profit.

If CP>SP, then it is loss.

Profit = SP - CP

Loss = CP - SP

Profit% = (Profit/CP) × 100

Loss% = (Loss/CP) × 100

CP → Cost Price

SP → Selling Price

Answer 2

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GIVEN:-

CP of Plot = 40,000.

SP = 6,000.

TO FIND:-

Gain & Loss.

SOLUTION:-

CP of 1 Shop = ₹4,000.

So,

CP of 16 Shops = ₹64,000.

Hence,

Total CP = ₹40,000 + ₹6,000 + 64,000

= ₹1,10,000.

there are 12 shops to or sold for ₹30,000 each and the remaining are sold at ₹10,000 each.

SP of 1 Shop = ₹30,000

SP of 2 Shops = ₹60,000

Shops Remaining = 12 - 2 = 10

SP of 1 Shop = ₹10,000

SP of 10 Shops = ₹1,00,000

So,

Total SP = ₹60,000 + ₹1,00,000

= ₹ 1,60,000

As we see that, total SP is more than total CP.

SP > CP.

Profit = SP - CP

= ₹1,60,000 - 1,10,000

= ₹50,000.

Profit % = ( Profit/CP )×100

= ( 50,000 / 1,10,000 )× 100

= 5/11 × 100

= 45.45%.

• I Hope it's Helpful My Friend.