a man purchased a table and chair for rupees 2000. he sold the table at a profit of 20% and the chair at the profit of 40%. in this way his total profit was 25% find the cost price in rupees of the table?
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Answer:
Let cost price of a table =x Rs and cost price of chair =y Rs.
Total cost =2000 Rs (Given)
∴x+y=2000 ...(1)
Table is sold at a profit of 20%.
∴Selling Price of table=CP+
100
CP×Profit Percentage
=x+
100
x×20
=
5
6x
Chair is sold at a profit of 30%
∴Selling Price of chair=CP+
100
CP×Profit Percentage
=y+
100
y×30
=
10
13y
∴Total selling price=
5
6x
+
10
13y
Given that, total profit =23%
∴Selling Price=CP+
100
CP×Profit
=2000+
100
2000×23
=2460 Rs
⇒
5
6x
+
10
13y
=2460
⇒12x+13y=24600 ...(2)
From equation (1), we get y=2000−x
Putting the value of y in equation (2),
We get 12x+13(2000−x)=24600
⇒26000−x=24600
∴x=1400
So, the cost price of the table is x=1400 Rs.
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