Math, asked by Niksnikita, 1 year ago

a man purchased some horses for rupees 3000. Three of them died , and he sold the rest at rupees 65 more than what he paid for each horse and thus gained 6 % on his outlay .How many horses did he buy??



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Answers

Answered by rk086466
53
, hope this is helpful
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Answered by vaduz
36

Answer:

15 horses

Step-by-step explanation:

let the no. of horses is n and cost of each horse is x

so n*x= 3000 --------1

as three horses died and rest are sell 65 rs more than cost price. so

(n-3)(x+65)= 3000*\frac{106}{100}\\\\nx+65n-195-3x=3180\\\\3000-195+65n-3x=3180\\\\65n-3x=375\\\\65n-3*\frac{3000}{n}=375\\\\65n^{2}-375n-9000=0\\\\13n^{2}-75n-1800=0

by solving this we get n=15

so there were total 15 horses he bought.

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