Math, asked by hansi28, 10 months ago

A man purchased some pigeons. 20% of them flew away and 5% died. He sold 45% of the
remaining pigeons. If now he has 33 pigeons, how many pigeons did he purchase?​

Answers

Answered by sahaneashwini281
20

Answer:

he purchased 80 pigeons

Step-by-step explanation:

let the total number of pigeons be x

so 20% flew and 5% died

that means a total of 25% gone

remaining=75%

out of those remaining 45% were sold

and 33 pigeons were remaining

thus,

75x/100-75x/100*45/100=33

3x/4-3x/4*9/20=33

3x/4-27x/80=33

60x/80-27x/80=33

60x-27x/80=33

33x/80=33

33x=80*33

thus,

x=80


hansi28: thank you so much
sahaneashwini281: welcome
Answered by seemamathur960
13

Answer:

X=80

Step-by-step explanation:

Let total no of pigeons be X

20% of them flew

20% of X= 20/100*X

=20X/100

5% of them died

5% of X = 5/100*X

=5X/100

Pigeons left=X-(20X/100+5X/100)

=X-25X/100

=100X-25X/100

=75X/100

45% of remaining were sold

45% of 75X/100=45/100*75X/100

=3375X/10000

=135X/400

Pigeons left=Remaining pigeons-

pigeons sold

33=75X/100-135X/400

33=300X-135X/400

33=165X/400

33*400=165X

13200=165X

13200/165=X

80=X

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