Math, asked by Siddu4916, 1 year ago

A man purchased two cows for Rs 500. He sells the first at 12% loss and the second at 8% gain. In this bargain he neither gains nor loss. Find the selling price of each cow.

Answers

Answered by mysticd
9
Hi ,

i ) cost price of first cow = Rs 500

Loss = L = 12%

Selling price ( s.p ) = c.p ( 100 - L )/100

= 500 × ( 100 - 12 )/100

= 500 × 88/100

= Rs 440 ----( 1 )

ii ) cost price of second cow = Rs 500

Gain = g = 8%

Selling price = c.p × ( 100 + g )/100

= 500 × ( 100 + 8 )/00

= 500 × ( 108/100 )

= Rs 540----( 2 )

Total cost price of two cows =Rs1000

Total s.p of two cows = ( 1 ) + ( 2 )

= 440 + 540

= Rs 980

Total Loss = total c.p - total s.p

= 1000 - 980

= Rs 20

Total loss =( loss × 100 )/ ( total c.p )

= ( 20 × 100 )/ 1000

= 2%

I hope this helps you.

: )
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