A man purchased two cows for Rs 500. He sells the first at 12% loss and the second at 8% gain. In this bargain he neither gains nor loss. Find the selling price of each cow.
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Hi ,
i ) cost price of first cow = Rs 500
Loss = L = 12%
Selling price ( s.p ) = c.p ( 100 - L )/100
= 500 × ( 100 - 12 )/100
= 500 × 88/100
= Rs 440 ----( 1 )
ii ) cost price of second cow = Rs 500
Gain = g = 8%
Selling price = c.p × ( 100 + g )/100
= 500 × ( 100 + 8 )/00
= 500 × ( 108/100 )
= Rs 540----( 2 )
Total cost price of two cows =Rs1000
Total s.p of two cows = ( 1 ) + ( 2 )
= 440 + 540
= Rs 980
Total Loss = total c.p - total s.p
= 1000 - 980
= Rs 20
Total loss =( loss × 100 )/ ( total c.p )
= ( 20 × 100 )/ 1000
= 2%
I hope this helps you.
: )
i ) cost price of first cow = Rs 500
Loss = L = 12%
Selling price ( s.p ) = c.p ( 100 - L )/100
= 500 × ( 100 - 12 )/100
= 500 × 88/100
= Rs 440 ----( 1 )
ii ) cost price of second cow = Rs 500
Gain = g = 8%
Selling price = c.p × ( 100 + g )/100
= 500 × ( 100 + 8 )/00
= 500 × ( 108/100 )
= Rs 540----( 2 )
Total cost price of two cows =Rs1000
Total s.p of two cows = ( 1 ) + ( 2 )
= 440 + 540
= Rs 980
Total Loss = total c.p - total s.p
= 1000 - 980
= Rs 20
Total loss =( loss × 100 )/ ( total c.p )
= ( 20 × 100 )/ 1000
= 2%
I hope this helps you.
: )
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