Question

A man purchased two TV sets for Rs. 42500. He sold one of them at a loss of 10% and others at profit of 10%. Find the cost price of both TV sets, if the selling price is same

Answer 1

Total cost of 2 TV sets = ₹42500
​Let the cost of First TV set be x
Then,
Cost of second TV set = ₹(42500-x)
Selling price of First TV set = x + 10% of x
                                              = 110x/100
Selling price of second TV set = (42500-x) - 10% of (42500-x)
                                                  = 90(42500-x)/100

S.P of First TV set = S.P of Second TV set
.: 110x/100 = 90(42500-x)/100
  11x = 9(42500-x)
         = 382500 - 9x
  20x = 382500
      x = 19125 
Cost Price of First set = ₹19125
​Cost Price of Second set = ₹23375
                                                 
 

Answer 2

Answer:

cost prize of 1 tv set=19125

cp of 2 tv set = 23375