a man purchases a bike for Rs 48,000. the value of the bike depreciates by 12% per annum.Find its value after 3 years
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Price of bike= 48,000
Rate of depreciation= 12%
T=3year
V = v.(1-r/100)^n
=48000(1-12/100)^3
48000-(88/100×88/100×88/100)
=48000×0.681472
=32,710.656 ans.
Rate of depreciation= 12%
T=3year
V = v.(1-r/100)^n
=48000(1-12/100)^3
48000-(88/100×88/100×88/100)
=48000×0.681472
=32,710.656 ans.
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