A man purchases a certain number of apples at 3 for 200 and same number of apples at 7 for 400. He sold eachat 65. Find the gain%
Answers
he buys a certain number at 3 mangoes per rupee.
he buys the same number at 4 mangoes per rupee.
he mixes them together and sells them at 3 mangoes per rupee.
let x = number of mangoes he buys.
if he gets 3 mangoes for 1 rupee, then his cost per mango is r/3.
if he gets 4 mangoes for 1 rupee, then his cost per mango is r/4.
he buys x at r/3 each for a total cost of xr/3.
he buys x at r/4 each for a total cost of xr/4.
his total cost is xr/3 + xr/4 which becomes 7xr/12.
when he sells the mangoes, he sells them for 3 mangoes per rupee.
his revenue for each mango is therefore equal to r/3.
his total revenue is equal to 2x * r/3 which is equal to 2xr/3.
he has a total revenue of 2xr/3.
he has a total cost of 7xr/12.
his total profit is equal to his total revenue minus his total cost.
this becomes 2xr/3 - 7xr/12 which becomes xr/12.
his rate of profit is equal to his total profit divided by his total cost.
this becomes xr/12 divided by 7xr/12.