Question

A man purchases two pens for Rs. 740. He sells one at 12 % profit and the other at a 8 %
loss. Then he neither gains nor loses. Find the cost price of each pen in Rs.).​

Answer 1

Answer:

CP of 2 pens = 740. Let CP of 1st pen is x and CP of 2nd pen is y.

Since there is no profit and loss in the whole transaction, so 12% of x = 8% of y

⇒x: y = 2: 3

Hence the cost of first pen = (2/3)×740 = Rs296 and that of the second pen = (3/5)×740 = Rs444

Answer 2

Given,

Cost of two pens= Rs.740

S.P of pens sold = 1st at 12% profit and the other at 8% loss.

To find,

Cost price of each pen = ?

Solution,

Let the cost of one pen be Rs.x and the cost of other pen be Rs.(740-x).

S.P. of one pen at 12% profit = 112÷100×X

S P. of other pen at 8% loss = 92÷100×X

Sale amount of two pens

= 1.12X+0.92X

= 2.04X

Sale amount = cost amount

2.04X = 740

X= 740÷2.04

=74000÷204

=363

The cost of one pen= Rs.363

The cost of other pen = Rs.740- Rs.363

= Rs.377

Hence,the cost price of first pen is Rs 363 and the cost of other is Rs.377.