Question

A man purchases two table lamps for rs 2430. By selling one table lamp at a profit of 6% and the other at a loss of 3% he neither gains nor losses on this transaction . Find the cost price of each lamp

Answer 1

Let the CP of the first lamp is = Rs. x
Then the CP of second lamp = Rs.(2430 - x)
Profit on selling first lamp = 6 %
Profit % = (Profit/CP × 100)%
6 = (Profit/x × 100)
50 profit = 3x
50(SP - CP) = 3x
50(SP - x) = 3x
Sp = Rs.(53x/50)
Loss on selling second lamp = 3 %
Lost % = (Loss/CP × 100)%
3 = (Loss2430 - x ×100)
100 Loss = 7290 - 3x
100(CP - SP) = 7290 - 3x
SP = Rs.(235710 - 97x/100)
Total Sp of both the lamps = (53x/50) + 235710 - 97x/100)
= Rs.(9x + 235710/100)
total CP of both lamps = Rs. 2430
Since there neither gain or loss in the transaction, so
Total SP of both lamps = total CP of both lamps
9x + 235710/100 = 2430
9x +235710 = 243000
9x = 7290
x = 7290 ÷ 9
x = 810
So CP of the first lamp = Rs. 810
Then CP of the second lamp = 2430 - 810 = Rs.1620

Answer 2

Answer:

Of 1 lamp cost price is 810 and of 2 nd lamp is 1620