Question

a man purchases two tables for rupees 4320 by selling one table at a profit of 15% and the other at a loss of 5% he nice again no roses in the whole transaction find the cost price of each table

Answer 1

Answer:

Cost price of each table was = 2057.1

Step-by-step explanation:

Given that

Price of two tables purchased in rupees = 4,320

Suppose,

Original price of first table being sold = x

Original price of second table being sold = x

Selling price of first table = x + 0.15x = 1.15x

Selling price of second table = x - 0.05x = 0.95x

Total amount earned from selling of tables is spend of buying two new tables, so

Price of new tables = total amount earned from selling two old tables

4320 = 1.15x + 0.95x

4320 = 2.10x

$x = \frac{4320}{2.10}$

x = 2057.1

So,

Cost price of each table was = 2057.1

Answer 2

Answer:

Rs 3220

Step-by-step explanation:

Let C.P of one table be x, So second table is Rs(4320 - x)

The profit will be 15% for first table.

Profit % will be Pr / C.P x 100

 15 = Pr / x   x 100

15 x = Pr(100)

100(S.P - C.P) = 15 x

S.P = 23 x / 20

Now loss on selling second table = 5%

loss % = loss / C.P x 100 %  

5 = (loss /4320 - x )  x 100

100(4320 - x - S.P) = 21,600 - 5 x

432000 - 100 x - 100 S.P = 21,600 - 5 x

S.P = 4,10,400 - 95 x / 100

S.P = 23 x / 20 + (4,10,400 - 95 x /100)

     = Rs (20 x + 4,10,400 / 100)

Total C.P = 4,320

 S.P = C.P because there is neither gain nor loss in the whole transaction.

   20 x + 4, 10,400 / 100 = 4,320

  20 x + 4,10,400 = 4,32,000

    x = 22000 / 20

 x = Rs 1100

C.P = 4,320 - 1100

C.P = Rs 3,220