a man purchases two tables for rupees 4320 by selling one table at a profit of 15% and the other at a loss of 9%, he neither gain nor loss in the whole transaction. Find the cost price of each table.
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sainkysaini59684:
My dear,
What?
Friend,just think, if two tables can be bought at 4320₹. Then how is it possible,that one table cost 4968 and......... Just think
Am I right dear?
It is wrong answer.
Yeah..sorry
I just thought of each
I have edited answer
Answered by
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Let price of a table is X
another table 4320 -X
X×115/100 =23X/20
(4320-X) ×91/100 = (393120 -91X )/100
ATQ
No profit No loss
so
23X/20 +(393120 -91X )/100 =4320
(115X + 393120 -91X)/100 =4320
24X= 432000- 393120
24X=38880
X= 38880/24
X=1620
CP of tables 1620 and (4320-1620=)2700
1620 (profit). 2700 (loss)
another table 4320 -X
X×115/100 =23X/20
(4320-X) ×91/100 = (393120 -91X )/100
ATQ
No profit No loss
so
23X/20 +(393120 -91X )/100 =4320
(115X + 393120 -91X)/100 =4320
24X= 432000- 393120
24X=38880
X= 38880/24
X=1620
CP of tables 1620 and (4320-1620=)2700
1620 (profit). 2700 (loss)
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