Question

A man purchases two watches for Rs.665. He sells
one at 20% profit and the other at 15% loss. Then he
neither gains nor loses. Find the selling price of each
watch.



plz reply as soon as possible and don't do spamming it is urgent
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Answer 1

Answer:

S.P. of first watch = 307.16

S.P. of second watch = 357.84

Explanation:

C.P of two watches =665

Let cost price of one watch be x

So C.P of other watch will be 665-x

Now, S.P of first watch= S.P of second watch (first with 20% profit and second with 15% loss)

So, x+20% of x= (665-x)-25% of (665-x)

On solving this, we get 6x/5=-3/4x + 1995/4

On solving further, x=255.769(approx.)

Therefore,

C.P of first watch=x=255.769

C.P of B=665-255.769=409.231

Now,

S.P. of first watch= (20% of 255.769)+ 255.769=307.16

S.P. of second watch= 409.231-(15% of 409.231)=357.84