A man pushes a 500 kg car initially at rest, with a constant force of 500
Newtons for a time of 10 seconds. Ignore any friction. What is the final
speed (velocity) of the car? *
Answers
Answered by
57
Answer:
10 m/s
Explanation:
Let the final velocity be 'v',
Initial velocity = u = 0(initially, at rest)
Final velocity = v
Using, v = u + at ,after 10 seconds,
=> v = 0 + a(10)
=> v = 10a
=> v/10 = a ...(1)
Given,
=> F = 500 N
=> ma = 500
=> 500a = 500
=> a = 1
From (1), a = v/10,
=> v/10 = 1
=> v = 10
Thus, final velocity of the car is 10 m/s
Answered by
31
Answer:
Given :-
- Mass = 500 kg
- Force = 500 N
- Time = 10 sec
To Find :-
Velocity
Solution :-
We know that
v = u + at
v = 0 + a(10)
v = 10a
v/10 = a
Now,
F = ma
500 = 500 × a
500/500 = a
1 = a
Now,
v/10 = 1
v = 10 × 1
v = 10 m/s
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