Question

A man pushes a block of 30kg along a level floor at constant speed with a force directed at 45degree below the horizontal. If coefficient of friction is 0.20the work done by man on block in pushing it through 20meter is

Answer 1

Block is moving with constant speed. Hence external force should be equal to friction.
FCos45 = μmg

Work done by man = FSCos45
W = μmgS
= 0.2 * 30 * 9.8 * 20
= 1176 J
= 1.176 kJ

Work done by man on block is 1.176 kJ

Answer 2

Explanation:

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