Question

A man pushes a book by applying a force of 6 N. Find the amount of work done by this force as the book is displaced through 30 cm along the direction of the push. solve it

Answer 1

GiveN :

• Force (F) = 6 N
• Displacement (s) = 30cm = 0.3 m

To FinD :

• Work Done by man

SolutioN :

We know that,

⇒Work Done = Force * Displacement

⇒W = F * s

⇒W = 6 * 0.3

⇒W = 1.8

$\therefore$ Work Done to displace book is 1.8 Joule.

Answer 2

Answer:

1.8 J

Explanation:

the equation for wok is,

Work , W = F.d

OR    W= F d cos ($theta$)                 {  F----> force

                                                          d---> displacement

                                                 theta---->  angle b/w force and displacement }  

In this question it is given that block moves along direction of push

that means, angle b/w force and displacement is zero  , that is, theta=0

Given , F = 6 N

          d= 30 cm  = 0.3 m

     cos (theta)= cos 0 = 1

therefore applying the values in abv highlighted equation,

W = 6 * 0.3 * cos 0

  = 6 * 0.3 * 1

 = 1.8 Joule

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                 hope it help u