Question

A man pushes a roller with a force of 50N through a distance of 20m.Calculate the work done of the handle of the roller is inclined at a angle of 60° with the ground

Answer 1

W=F.S.Cos theta
=50×20×Cos 60
=1000×1/2
= 500 joules

hope this helps you.....

Answer 2

Given - Force, distance and angle

Find - Work done

Solution - Work done can be calculated as - Force*displacement*cos theta

Keep the values in formula to find the work done.

Work done = $50 \times 20 \times \cos(60)$

Keep the value of cos(60)

Work done = $50 \times 20 \times \frac{1}{2}$

Performing division

Work done = $50 \times 10$

Performing multiplication

Work done = 500 Joules

Hence, the work done of handle is 500 Joules.