A man raises a box of mass of 50 kg to a height of 2 m in 20 s, while another man raises the
same box to the same height in 50 s.
(a) Compare: (i) the work done and (ii) the power developed by them.
(b) Calculate (i) the work done and (ii) the power developed by each man. (g =10 Nkg-1
)
Answers
Answered by
2
Answer:
Work done in raising a 50kg mass to a height 2m against the force of gravity is: W = mg × h = mgh
Hence both men will do the same amount of work.
Hence, work done by A/work done by B = mgh/mgh = 50 x 10 x 2/50 x 10 x 2 = 1/1 = 1: 1
(ii) First man A takes 2 minutes to raise 50 kg mass Second man B takes 5 minutes to raise 50 kg mass.
Power developed by man A = work done/Time taken mgh/t = 50 x 10 x 2J/120S = 25/3W
Power developed by man B = work done/Time taken = mgh/t = 50 x 10 x 2J/5 x 60s = 10/3 W Power developed α 1/time taken
Power developed by A/Power developed by B = (25/3)/(10/3) = 25/10 = 5/2 = 5 : 2
Hope it helps..
Similar questions
English,
4 months ago
Science,
4 months ago
English,
9 months ago
Environmental Sciences,
1 year ago
English,
1 year ago