Science, asked by krutharthacoorg, 9 months ago

A man raises a box of mass of 50 kg to a height of 2 m in 20 s, while another man raises the

same box to the same height in 50 s.

(a) Compare: (i) the work done and (ii) the power developed by them.

(b) Calculate (i) the work done and (ii) the power developed by each man. (g =10 Nkg-1

) ​

Answers

Answered by 21532kumarisonianaga
2

Answer:

Work done in raising a 50kg mass to a height 2m against the force of gravity is: W = mg × h = mgh

Hence both men will do the same amount of work.

Hence, work done by A/work done by B = mgh/mgh = 50 x 10 x 2/50 x 10 x 2 = 1/1 = 1: 1

(ii) First man A takes 2 minutes to raise 50 kg mass Second man B takes 5 minutes to raise 50 kg mass.

Power developed by man A = work done/Time taken mgh/t = 50 x 10 x 2J/120S = 25/3W

Power developed by man B = work done/Time taken = mgh/t = 50 x 10 x 2J/5 x 60s = 10/3 W Power developed α 1/time taken

Power developed by A/Power developed by B = (25/3)/(10/3) = 25/10 = 5/2 = 5 : 2

Hope it helps..

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