Math, asked by 1234596, 11 months ago

a man reads 3/8 of a day and 4/5of the remainder on thevsecond day. if the number of pages still unread 40 then how many pages did the book contain?​

Answers

Answered by sujal382
3

Answer:

320 pages

Step-by-step explanation:

The part remaining after 1 day =

 \frac{5}{8}

If he reads 4/5 of the book them the party remaining is 1/5.

 \frac{5}{8} x \times  \frac{1}{5}  = 40

 \frac{5}{40} x = 40

320=×

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