Question

A man reared cows and buffaloes. The
number of buffaloes was 7 more than
one-third of the number of cows. What
was the total number of animals, if the
number of buffaloes was 21?
80
TA​

Answer 1

Answer:

no. of buffaloes = 21

1/3x + 7=21

1/3x=21-7

1/3x=14

x=14×3

x= 42

no. of cows is 42

total no.of animals=42+21=63

Step-by-step explanation:

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Answer 2

$\huge{\blue{\bold{\underline{\underline{Answer :}}}}}$

$\:\:$

$\large{\green{\underline \bold{\tt{Given :-}}}}$

$\:\:$

• The number of buffaloes was 7 more than one-third of the number of cows

$\:\:$

• The number of buffaloes was 21

$\:\:$

$\large{\red{\underline \bold{\tt{To \: Find :-}}}}$

$\:\:$

• Total number of animals

$\:\:$

$\large{\orange{\underline{\tt{Solution :-}}}}$

$\:\:$

• Let the total number of Buffalo be "B"

• Let the total number of Cow be "C"

$\:\:$

$\purple{\underline \bold{According \: to \: the \ question :}}$

$\:\:$

The number of buffaloes was 7 more than one-third of the number of cows

$\:\:$

➜ $\sf B = \dfrac { 1 } { 3 } \times C + 7$

$\:\:$

Also given that , number of buffaloes was 21

$\:\:$

Thus,

$\:\:$

➨ B = 21

$\:\:$

So,

$\:\:$

➜ $\sf 21 = \dfrac { C } { 3 } + 7$

$\:\:$

➜ $\sf 21 = \dfrac { C + 21 } { 3 }$

$\:\:$

➜ 63 = C + 21

$\:\:$

➜ C = 63 - 21

$\:\:$

➨ C = 42

$\:\:$

• Hence the number of Cow is 42

$\:\:$

Given that the number of Buffalo is 21

$\:\:$

$\underline{\bold{\texttt{Total number of animals :}}}$

$\:\:$

Number of Buffalo + Number of Cow

$\:\:$

➜ 21 + 42

$\:\:$

➨ 63

$\:\:$

• Hence total number of animals is 63

$\:\:$

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