A man reduces his speed from 20 kmph to 18 kmph. So, he takes 10 minutes more than the normal time. what is the distance traveled by him.
A.30 km
B.25 km
C.50 km
D.36 km
Answers
Answered by
1
Usual time = 9*10 = 90 min = 3/2 h
Thus,
Distance traveled = Speed * time = 20*(3/2) = 30 km.
Alternatively,
As the speed decreases from 20 kmph to 18 kmph i.e. 10 % increment in usual time.
10 % = 10 min
100 % = 100 min.
Now, = (100/60 h) *18
= 30 km.
Thus,
Distance traveled = Speed * time = 20*(3/2) = 30 km.
Alternatively,
As the speed decreases from 20 kmph to 18 kmph i.e. 10 % increment in usual time.
10 % = 10 min
100 % = 100 min.
Now, = (100/60 h) *18
= 30 km.
Similar questions
Hindi,
7 months ago
Social Sciences,
7 months ago
Math,
1 year ago
Math,
1 year ago
Biology,
1 year ago