A man repay a loan of rs 6500 by paying rs 610 in the first month and decrease the payment by rs 30 per month how long will it take to clear his loan
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610 , 580 , .....
a = 610
d = -30
n = no. of months
sn = 6500
sn = n/2(2a + (n-1)(d))
6500 = n/2 (2(610) + (n-1)(-30))
13000 = n( 1220 + -30n + 30)
13000 = 1220n - 30n^2 + 30n
13000 = 1250n - 30n^2
30n^2 - 1250n + 13000 = 0
3n^2 - 125n + 1300 = 0
3n^2 - 65n - 60n + 1300 = 0
n(3n - 65) - 20(3n - 65) = 0
(n-20)(3n-65) = 0
n = 20
3n = 65 n = 65/3
Months can't be in decimals
So n = 20
It will take 20 months to repay the loan.
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a = 610
d = -30
n = no. of months
sn = 6500
sn = n/2(2a + (n-1)(d))
6500 = n/2 (2(610) + (n-1)(-30))
13000 = n( 1220 + -30n + 30)
13000 = 1220n - 30n^2 + 30n
13000 = 1250n - 30n^2
30n^2 - 1250n + 13000 = 0
3n^2 - 125n + 1300 = 0
3n^2 - 65n - 60n + 1300 = 0
n(3n - 65) - 20(3n - 65) = 0
(n-20)(3n-65) = 0
n = 20
3n = 65 n = 65/3
Months can't be in decimals
So n = 20
It will take 20 months to repay the loan.
Mark as brainliest.
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