Question

A man repays a loan of 365.000 by paying 3400 is the first month and the increasing the
payment by 3300 every monta How long will it take for to dear the loan?​

Answer 1

Hlo mate here is ur ans.......

Step 1 : This is an Arithmetic progression.

Step 1 : This is an Arithmetic progression.The sum of an Arithmetic progression is given by :

Step 1 : This is an Arithmetic progression.The sum of an Arithmetic progression is given by :Sn = n/2 [2a + (n - 1) d]

Step 1 : This is an Arithmetic progression.The sum of an Arithmetic progression is given by :Sn = n/2 [2a + (n - 1) d]Where :

Step 1 : This is an Arithmetic progression.The sum of an Arithmetic progression is given by :Sn = n/2 [2a + (n - 1) d]Where :Sn = The sum (total amount to be paid)

Step 1 : This is an Arithmetic progression.The sum of an Arithmetic progression is given by :Sn = n/2 [2a + (n - 1) d]Where :Sn = The sum (total amount to be paid)n = The number of terms.(number of months taken to clear the payment )

Step 1 : This is an Arithmetic progression.The sum of an Arithmetic progression is given by :Sn = n/2 [2a + (n - 1) d]Where :Sn = The sum (total amount to be paid)n = The number of terms.(number of months taken to clear the payment )a = The first term (The first amount to be paid)

Step 1 : This is an Arithmetic progression.The sum of an Arithmetic progression is given by :Sn = n/2 [2a + (n - 1) d]Where :Sn = The sum (total amount to be paid)n = The number of terms.(number of months taken to clear the payment )a = The first term (The first amount to be paid)d = The common difference.(The amount by which the payment increases)

Step 1 : This is an Arithmetic progression.The sum of an Arithmetic progression is given by :Sn = n/2 [2a + (n - 1) d]Where :Sn = The sum (total amount to be paid)n = The number of terms.(number of months taken to clear the payment )a = The first term (The first amount to be paid)d = The common difference.(The amount by which the payment increases)Step 2 : Identify the given values in the given problem

Pls refer to the attachment above....

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Answer 2

Answer:

see the attachment

Explanation:

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