A man required less than 9 days than his son to complete a job.Together they can finish the job in 20 days.How many days would each requires to finish the alone?
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(15×20×25)÷(15×20+15×25+25×20)=6(18÷47)or 6.38
Therefore they would each take 6.38 days to complete the job.
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Answer:
Let the time required by the son to finish the job is x days.
Then, the man would finish the job in x-9 days.
Son's One day work = 1/x
Man one day work = 1/x-9
(Son + Man) one day work = 1/x +1/x-9 = 1/20
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