Question

A man rides his bike from point A to point D. There are two points B and C between A and D respectively. He rides from A to B at a speed of 20 km/h, from B to C at a speed of 30 km/h and from C to D at a speed of 60 km/h. Assuming that the distance from B to C is 1.5 times longer than the distance from A to B; the distance from C to D is twice longer than the distance from A to B. What is the man's average speed?

Answer 1

For this, We have to find the time taken to cover distance between A to B, B to C and C to D.

Then, find the distance between A to B ,B to C and C to D.

After finding use this formula

$\boxed{\green{\bold{ Average\: Speed }}}$${\red{ = \frac{ sum \:of\: distance}{sum \:of \:time} }}$