A man riding a bike with front and back wheel circumference of 40 inches and 70 inches respectively.if the man ride the bike on a straight road without slipage,how many inches will the man have travelled when the front wheel has made 15 revolution more than the back wheel
Answers

14
Q:
A man is riding a bike with front and back wheel circumference of 40 inches and 70 inches respectively. If the man rides the bike on a straight road without slippage, how many inches will the man have travelled when the front wheel has made 15 revolutions more than the back wheel?
A) 1100B) 1300C) 1400D) 1200
Answer: C) 1400
Explanation:
Given the ratio of the circumference of front wheel is 40 inches and back wheel is 70 inches.
Distance covered = Circumference of the wheel × No. of Revolutions made by the wheel
If n is the number of revolutions made by back wheel, the number of revolutions made by front wheel is n+15
Distance covered by both the wheels is the same
i.e, 40*(n+15)=70n
n=20
Front wheel : Back Wheel
Circumference 40 : 70
Revolutions 35 : 20
Distance covered : 40×35 = 70×20 = 1400 inches.
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circumference of front wheel = 40 inches
circumference of back wheel = 70 inches
now the man rides the bikes on a straight road without slippage.
Let number of revolutions made by front wheel is n
then number of revolutions made by back wheel = n - 15
in case of distance travelled by bike ,
distance covered by back wheel = distance covered by front wheel
so, 70(n - 15) = 40n
=> 70n - 1050 = 40n
=> 30n = 1050
=> n = 35
now, distance travelled = 40n = 70(n - 15)
= 1400 inches