a man riding on a bicycle covers a distance of 60 km in a direction of the wind and comes back to the his original position in 8 hours. another cyclist with the same speed of bicycle riding on a bicycle at the same time covers a distance of 45 km in the direction of wind and returns back half of its distance in 3 hours and 45 minutes. find the speed of bicycle and speed of wind
Answers
D1=60km
T1=8 hours
D2=45km
T2=(3 hours,45min)*2 = 7.5
Speed of bicycle=x
Speed of wind=y
V1 =x+y
V2=x-y
• Formula=d/v=t
60/x+y =8
7.5-x=y
45/x-y =7.5
-6+x=+y
• Equating for y
7.5-x=-6+x
13.5/2=x
X=6.75km/hour
• Value of y from equa -6+x=y :
-6+6.75=y
0.75km/hour=y
Speed of bicycle is 6.75 km/hour
Speed of wind is 0.75km/hour
Answer:15 km/hr
Step-by-step explanation: speed of wind 10km/hr
let x-10 be the speed for going against the wind
Speed with wind be x+10
60/x+10 +. 60/x-10 = 8
Multiple by both sides by (x+10)(x-10)
60(x+-10)+60(x+10)=8(x+10)(x-10)
60x-600+60x+600=8xsquare-800
8xsquare-120x-800=0
Divided by 8
X square - 15x - 100 = 0
X square-20x+5x-100=0
X(x+20) 5 (x+20) = 0
X-20=0 &. X+5=0
X. = 20. &. X. = -5
Speed is positive
X=20
Speed of bicycle=20km/hr