A Man runs 200 Metre in 25 seconds finds
Answers
Answered by
0
Answer:
and this you full q
man runs 200 m in first 25 s and then turns back and run 100 m in next 15 s towards the starting point. Find out his
(a) average velocity and (b) his average speed.
Step-by-step explanation:
Given,
In first event, displacement S=200m in time t
1
=25sec
In second event, displacement S=−100m in time t
1
=15sec
Average velocity=
total time
Total displacement
=
t
1
+t
2
S+(−S)
=
25+15
200+(−100)
=2.5ms
−1
Average speed=
total time
Total distance
=
t
1
+t
2
S+S
=
25+15
200+100
=10ms
−1
Hence, Average velocity 2.5ms
−1
and average speed is 10ms
−1
Answered by
0
Answer:
if it is speed here is ur answer
Step-by-step explanation:
200/25=40/5=8
8m/s
Similar questions