Question

A man runs across the roof of a tall building and jumps horizontally on to the (lower) roof of an adjacent building. If his speed is 9 m s⁻¹ and the horizontal distance between the building is 10 m and the height difference between the roofs is 9 m. Will he be able to land on the next building? (Take g = 10 m s⁻²).

Answer 1

Hii dear,

# Answer- Yes. Man will safely land on other building.

# Given-
h = 9 m
s = 10 m
u = 9 m/s

# Formula-
Time taken by man to fall through height h,
t = √(2h/g)
t = √(2×9/10)
t = 1.34 s

Horizontal distance travelled by man in this time,
y = ut
y = 9×1.34
y = 12.06 m

As horizontal distance travelled by man before falling is greater than distance between buildings he'll safely reach the other building.

Hope that is useful...

Answer 2

Given :

Horizontal speed of man =u=9 m/s

Difference of heights between two buildings is =h=9m

g=10m/s2²

Time of flight=t= √[2h/g]

=√2x9/10

=1.341 sec

Horizontal distance travelled by man =dm= Horizontal speed x time of flight

=uxt

=9x1.341

=12.07 m

Given that the horizontal distance between two buildings db=10m

Since dm>db, the man can land on the next building safely