A man runs across the roof top of a tall building and jumps horizontally with the hope of landing on the
roof of the next building which is of a lower height than the first. If his speed is 9m/s, the horizontal distance between the two buildings is 10 m and the height difference is 9 m will he be able to land on the next building ? (take g = 10 m/s")
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2
Answer:
First we need to find the time, t of the jump.
which is, t=√[(10*2/9.8)]
And then multiply t with the velocity v
Answered by
1
Hey brainly user!
Here is your answer
Horizontal velocity =9m/s
height difference h=9m
acceleration due to gravity (g) =10m/s^2
Distance between the building d=10m
Horizontal Range (R) =u√2h/g
R=9√2×9/10
R=9√1.8
R=12.074m
Horizontal range is greater than distance between the two buildings. Hence man able to land on the next building
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