Physics, asked by SiddharthDash, 11 months ago

A man runs across the roof top of a tall building and jumps horizontally with the hope of landing on the
roof of the next building which is of a lower height than the first. If his speed is 9m/s, the horizontal distance between the two buildings is 10 m and the height difference is 9 m will he be able to land on the next building ? (take g = 10 m/s")

Answers

Answered by abeer1133

Answer:

First we need to find the time, t of the jump.

which is, t=√[(10*2/9.8)]

And then multiply t with the velocity v

Answered by Anonymous

Hey brainly user!

Here is your answer

$<b><body bgcolor="lightpink"><fontcolor="black">$

$\boxed{\sf\blue{Answer=12.074}}$

Horizontal velocity =9m/s

height difference h=9m

acceleration due to gravity (g) =10m/s^2

Distance between the building d=10m

Horizontal Range (R) =u√2h/g

R=9√2×9/10

R=9√1.8

R=12.074m

Horizontal range is greater than distance between the two buildings. Hence man able to land on the next building

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