Question

a man's age is 3 times his son's age after 10 years he is 5 times his son's age find the current ages

Answer 1

Let man's age be x and son's age be y

x=3y

(x+10)=5(y+10)

x+10=5y+50

3y+10=5y+50

2y=40

y=20

x=3y

=3×20

=60

Man's age is 60 years and son's age is 20 years!

Answer 2

Hey mate!

Here's your answer!!

Let man’s son’s age be x years. Therefore, man’s age will be 3x years. Ten years ago, their age was (x − 10) years and (3x − 10) years respectively.

According to the question,

10 years ago, man’s age = 5 × man’s son’s age 10 years ago

3x − 10 = 5(x − 10)

3x − 10 = 5x − 50

Transposing 3x to R.H.S and 50 to L.H.S, we obtain

50 − 10 = 5x − 3x

40 = 2x

Dividing both sides by 2, we obtain

20 = x

Man’s son’s age = x years = 20 years

Man’s age = 3x years = (3 × 20) years = 60 years

$hope \: it \: helps \: you.$
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