Question

A man's age is 3 times that of his son and In 12 years he will be twice as old as his son would be. What are their present age? use linear equations

Answer 1

let the man's age be x
and the son's age be y
x = 3y. -------( 1 )
x + 12 = 2(y + 12)
from ( 1 )
3y + 12 = 2y + 24
y = 12 years
x = 3y
= 3 × 12 = 36 years. ANSWER.
thanks...

Answer 2

Hi there!

here's the answer


let son's age be x

man's age = 3x

After 12 years age of :

son = x + 12 years

man = 3x + 12 years

in order to balance the equation,
we have,

$2(x + 12) = 3x + 12$

$2x + 24 = 3x + 12$

$24 - 12 = 3x - 2x$

$12 = x \: or \: x = 12$


so

son's age = x = 12 years

man's age = 3x = 3 × 12 = 36 years