Question

A man's age is 3 times that of his son and in 12 years he will be twice as old as his son would be. What are their present ages? solve using linear equation

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

let the son age be x and the man age be 3x

aftet 12 years

3x +12 =2 (x + 12)

3x + 12 = 2x + 24

3x - 2x = 24 - 12

x = 12

so, son's age is 12 years
and man age is 3x = 3× 12 = 36 years