Question

a man's age is 3 times the age of his two sons. after 5 years his age will be twice the sum of the ages of his two sons. find the age of the man

Answer 1

let the ages of two sons be x1, and x2, and the age of their father be y. then;

y = 3(x1+x2)
x1+x2 = y/3

after 5 years;
(y+5) = 2(x1+x2+10)
y+5 = 2{(y/3)+10}
y-(2/3)y = 20-5
(1/3)y = 15
y = 45

hence the age of the man is 45 years.

Answer 2

Answer:

Step-by-step explanation given below:

let the ages of two sons be x1, and x2, and the age of their father be y. then;

y = 3(x1+x2)

x1+x2 = y/3

after 5 years;

(y+5) = 2(x1+x2+10)

y+5 = 2{(y/3)+10}

y-(2/3)y = 20-5

(1/3)y = 15

y = 45

hence the age of the man is 45 years.

thanku